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jmc

prealgebra junior

Problem

\frac{\frac{3}{8} + \frac{7}{8}}{\frac{4}{5}} =

(A)

1

(B)

\frac{25}{16}

(C)

2

(D)

\frac{43}{20}

Solution

\frac{\frac{3}{8} + \frac{7}{8}}{\frac{4}{5}} = \frac{\frac{10}{8}}{\frac{4}{5}} = \frac{\frac{5}{4}}{\frac{4}{5}} = \frac{5}{4} \cdot \frac{5}{4} = \frac{25}{16} = \frac{25}{16}

Final answer

B