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geometry intermediate

Problem

A point is outside a circle and is inches from the center. A secant from cuts the circle at and so that the external segment of the secant is inches and is inches. The radius of the circle is:
(A)
(B)
(C)
(D)
Solution
Using the Secant-Secant Power Theorem, you can get , where is the radius of the given circle. Solving the equation, you get a quadratic: . A radius cannot be negative so the answer is
Final answer
C