jmc

Question

A sequence starts with the term 2222. Each succeeding term is found by adding 1010 to the previous term. What is the sum of the sixth and seventh terms?

Accepted Answer

The nth term of the sequence is 2222+1010(n-1). Therefore, the sum of the sixth and seventh terms is 2222+1010(5)+2222+1010(6)=4444+1010(11)=4444+11110=15554.