Browse · harp Print → smc prealgebra intermediate Problem If a=1, b=10, c=100, and d=1000, then (a+b+c−d)+(a+b−c+d)+(a−b+c+d)+(−a+b+c+d) is equal to (A) 1111 (B) 2222 (C) 3333 (D) 1212 Solution — click to reveal Adding all four of the equations up, we can see that it equals 3(a+b+c+d) This is equal to 3(1111)=3333 Final answer C ← Previous problem Next problem →