Browse · harp Print → jmc prealgebra junior Problem 1−322= (A) −3 (B) −34 (C) 32 (D) 2 (E) 6 Solution — click to reveal Just simplify the bottom as 33−32=31, getting us 312, with which we multiply top and bottom by 3, we get 16, or 6 6 Final answer E ← Previous problem Next problem →