jmc

As we are told, we want to find all values of $n>1$ such that $n$ divides into $171-80=91$ and $n$ also divides into $468-13=455$. We notice that $455=5\cdot 91$, so it follows that if $n$ divides into $91$, then it must divide into $455$. Then, we only need to find the factors of $91$, which are $\{1,7,13,91\}$. Summing the factors other than $1$ gives $7+13+91=\boxed{111}$.