jmc

The pattern repeats with every 8 letters, so we can determine the letter in the $n$th position by finding the remainder when $n$ is divided by 8. We can check that 2008 is a multiple of 8. That means 2010 has a remainder of 2 when divided by 8. The letter in the $2010$th position will be the same as the letter in the second position of the pattern, which is $\boxed{A}$.