The number halfway between 16 and 14 is

The number halfway between is the average. 16 + 142 = 212 + 3122 = 524

jmc

prealgebra junior

Problem

The number halfway between

\frac{1}{6}

and

\frac{1}{4}

(A)

\frac{1}{10}

(B)

\frac{1}{5}

(C)

\frac{5}{24}

(D)

\frac{7}{24}

Solution

The number halfway between is the average.

\frac{\frac{1}{6} + \frac{1}{4}}{2} = \frac{\frac{2}{12} + \frac{3}{12}}{2} = \frac{5}{24}

Final answer