Browse · MATH Print → jmc algebra junior Problem Let a, b, and c be the roots of 2x3+3x2+4x+5=0. Find abc+a+b+c. Solution — click to reveal By Vieta's formulas, abc=−25 and a+b+c=−23. Thus, abc+a+b+c=−25−23=−4. Final answer -4 ← Previous problem Next problem →