Browse · MATH Print → jmc algebra senior Problem Suppose that 4a=5, 5b=6, 6c=7, and 7d=8. What is a⋅b⋅c⋅d? Solution — click to reveal Because 4a⋅b⋅c⋅d=(((4a)b)c)d=((5b)c)d=(6c)d=7d=8=43/2,we have a⋅b⋅c⋅d=23. Final answer \frac{3}{2} ← Previous problem Next problem →