Cross-multiplying leaves align*x^28 &= 8 x^2 &= 64 x^2 &= 64 x &= 8align* So the answer is 8.

smc

prealgebra intermediate

Problem

\frac{\frac{x}{4}}{2} = \frac{4}{\frac{x}{2}}

, then

x =

(A)

\pm \frac{1}{2}

(B)

\pm 1

(C)

\pm 2

(D)

\pm 4

(E)

\pm 8

Solution

Cross-multiplying leaves

\frac{x ^{2}}{8} x^{2} x^{2} x = 8 = 64 = 64 = \pm 8

So the answer is

\pm 8

Final answer