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Printimc
prealgebra intermediate
Problem
The average (mean) of numbers is , and the average of other numbers is . What is the average of all numbers?
(A)
(B)
(C)
(D)
Solution
Since the average of the first numbers is , their sum is . Since the average of other numbers is , their sum is . So the sum of all numbers is Therefore, the average of all numbers is
Final answer
B