Browse · MATH Print → jmc algebra intermediate Problem Given a⋆b=a2+2ab+b2, what is the value of a⋆b when a=4 and b=6? Solution — click to reveal Note that a⋆b=a2+2ab+b2=(a+b)2. Thus, 4⋆6=(4+6)2=102=100. Final answer 100 ← Previous problem Next problem →