Browse · harp Print → smc algebra intermediate Problem If 10log109=8x+5 then x equals: (A) 0 (B) 21 (C) 85 (D) 89 Solution — click to reveal Notice that 10log109=9. Therefore, the condition we are looking for is 9=8x+5, or x=21. So the answer is 21 Final answer B ← Previous problem Next problem →