Browse · MATH Print → jmc algebra intermediate Problem If x is a real number, find 49x2+14x(19−7x)+(19−7x)2. Solution — click to reveal 49x2+14x(19−7x)+(19−7x)2=(7x)2+2(7x)(19−7x)+(19−7x)2=[7x+(19−7x)]2=192=361. Final answer 361 ← Previous problem Next problem →