jmc

Consider points $P$, $Q$, and $R$. If the slope between point $P$ and point $Q$ is the same as the slope between point $Q$ and point $R$, $P$, $Q$, and $R$ are collinear. So we must find the slopes between every pair of possible points. Let us name the points: $A=(2,2)$, $B=(9,11)$, $C=(5,7)$, and $D=(11,17)$. We make a chart of all possible pairs of points and calculate the slope:

\begin{array}{c|c} Points& Slope \\ \hline \vspace{0.05in} A,B&$\frac{11-2}{9-2}=\frac{9}{7}$\\ \vspace{0.05in} $A,C%%DISP_0%%amp;$\frac{7-2}{5-2}=\frac{5}{3}$\\ \vspace{0.05in} $A,D%%DISP_0%%amp;$\frac{17-2}{11-2}=\frac{15}{9}=\frac{5}{3}$\\ \vspace{0.05in} $B,C%%DISP_0%%amp;$\frac{7-11}{5-9}=\frac{-4}{-4}=1$\\ \vspace{0.05in} $B,D%%DISP_0%%amp;$\frac{17-11}{11-9}=\frac{6}{2}=3$\\ \vspace{0.05in} $C,D%%DISP_0%%amp;$\frac{17-7}{11-5}=\frac{10}{6}=\frac{5}{3}$ \end{array}As we can see, the slopes between $A$ and $C$, $A$ and $D$, and $C$ and $D$ are the same, so $A$, $C$, and $D$ lie on a line, Thus $B$, or the point $\boxed{(9,11)}$, is not on the line.