smc

We shall begin by eliminating some options through counterexamples. If $a=b=c=d=e$, then $m=k=l=a$, so $p=a$, and $m=p$. Answers (C) and (D) do not allow for $m=p$, so they can be eliminated. If we set $a=60$ and $b=c=d=e=0$, then $m=12$, $k=30$, $l=0$, and $p=15$. Here, $m<p$, so we can throw out options (A) and (B) as well. Now, we are left with only option $\boxed{\text{none of these}}$.