The fraction a2+x2a2+x2−a2+x2x2−a2 reduces to:
(A)
0
(B)
a2+x22a2
(C)
(a2+x2)232x2
(D)
(a2+x2)232a2
Solution — click to reveal
Multiplying the numerator and denominator by a2+x2 results in (a2+x2)(a2+x2)a2+x2−x2+a2=(a2+x2)(a2+x2)2a2. Since a2+x2=(a2+x2)21, the denominator is (a2+x2)2⋅(a2+x2)21=(a2+x2)23(a2+x2)232a2.