Browse · MATH Print → jmc algebra junior Problem Expand (x+10)(2y+10). Solution — click to reveal We apply the distributive property repeatedly:(x+10)(2y+10)=x(2y+10)+10(2y+10)=x⋅2y+x⋅10+10⋅2y+10⋅10=2xy+10x+20y+100. Final answer 2xy + 10x + 20y + 100 ← Previous problem Next problem →