Browse · MATH Print → jmc algebra junior Problem Let d and e denote the solutions of 2x2+3x−5=0. What is the value of (d−1)(e−1)? Solution — click to reveal Since 0=2x2+3x−5=(2x+5)(x−1), we have d=−25 and e=1.So (d−1)(e−1)=0. Final answer 0 ← Previous problem Next problem →