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jmc

prealgebra senior

Problem

According to the data shown, how much cheaper, in cents, is the cheaper store's price for Camera compared to the more expensive? \begin{array}{|l|l|} \hline \textbf{Store}& \textbf{Sale Price for Camera $X$} \\ \hline Super Savers & $\$9$~off the list price~$\$39.96$ \\ \hline Penny Wise & $25\%$~off the list price~$\$39.96$ \\ \hline \end{array}
Solution
The price at Super Savers is \39.96-\9=\30.96.0.75(\39.96)=\29.97.\30.96-\29.97=\boxed{99}$ cents.
Final answer
99