Browse · MATH Print → jmc algebra intermediate Problem Let f(x) be a polynomial such that f(x2+1)=x4+4x2.Find f(x2−1). Solution — click to reveal Let y=x2+1. Then x2=y−1, and x4=y2−2y+1, so f(y)=(y2−2y+1)+4(y−1)=y2+2y−3.Hence, f(x2−1)=(x2−1)2+2(x2−1)−3=x4−4. Final answer x^4 - 4 ← Previous problem Next problem →