Browse · harp Print → smc algebra senior Problem If i2=−1, then (1+i)20−(1−i)20 equals (A) −1024 (B) −1024i (C) 0 (D) 1024 Solution — click to reveal Notice that (1+i)2=2i and (1−i)2=−2i. Therefore, (1+i)20−(1−i)20=(2i)10−(−2i)10=(2i)10−(2i)10=0,0. Final answer C ← Previous problem Next problem →