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prealgebra intermediate

Problem

The value of

[2 - 3 (2 - 3)^{- 1}]^{- 1}

is:

(A)

5

(B)

- 5

(C)

\frac{1}{5}

(D)

- \frac{1}{5}

Solution

\frac{1}{2 - 3 ( - 1 )} = \frac{1}{5}

, so the answer is

\frac{1}{5}

.

Final answer

C