Browse · MATH Print → jmc algebra junior Problem Let the operation # be defined as #(a,b,c)=b2−4ac, for all real numbers a,b and c. What is the value of #(1,2,3)? Solution — click to reveal Substitute 1 for a, 2 for b, and 3 for c in the expression b2−4ac to find that #(1,2,3)=22−(4)(3)(1)=−8. Final answer -8 ← Previous problem Next problem →