Browse · MATH Print → jmc prealgebra intermediate Problem Solve for a: 3a−7(3−a)=5. Express your answer as a common fraction in simplest form. Solution — click to reveal Distributing the -7 gives 3a−7(3−a)=3a−21+7a=10a−21=5. We now add 21 to both sides to get 10a=26, and a=513. Final answer \frac{13}{5} ← Previous problem Next problem →