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prealgebra junior

Problem

\frac{2}{25} =

(A)

.008

(B)

.08

(C)

.8

(D)

1.25

Solution — click to reveal

\frac{2}{25} = \frac{2 \cdot 4}{25 \cdot 4} = \frac{8}{100} = 0.08 \to .08

Final answer

B

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