Browse · MATH Print → jmc algebra intermediate Problem Simplify 15t424t3⋅3t65t8. Solution — click to reveal 15t424t3⋅3t65t8=1524⋅t4t3⋅35⋅t6t8=58⋅t1⋅35⋅t2=(58⋅35)⋅(t1⋅t2)=38⋅t=38t. Final answer \frac{8t}{3} ← Previous problem Next problem →