jmc

Expanding the left side of the given equation, we have $x^2-x-6=14\Rightarrow x^2-x-20=0$. Since in a quadratic with equation of the form $a{x}^2+bx+c=0$ the product of the roots is $c/a$, the product of the roots of the given equation is $-20/1=\boxed{-20}$.