smc

Replacing $x$ with $-x,$ we have the graph of $y=a(-x{)}^2+b(-x)+c=a{x}^2-bx+c.$ We can plug in simple values of $a,b,$ and $c$ for convenient drawing. For example, we can graph $x^2+2x+1$ and $x^2-2x+1.$ We see that the parabolas intersect at $(0,1),$ which is on the y-axis. The answer is $\boxed{\text{in one point on the y-axis}}.$