32+54+98+1716+3332+6564-7=

Simplifying, we have 9664+8064+7264+6864+6664+6564-7, which is 96+80+72+68+66+6564-7 = 44764-7 = 66364-7 = -164.

smc

prealgebra intermediate

Problem

\frac{3}{2} + \frac{5}{4} + \frac{9}{8} + \frac{17}{16} + \frac{33}{32} + \frac{65}{64} - 7 =

(A)

- 1/64

(B)

- 1/16

(C)

0

(D)

1/16

Solution

Simplifying, we have

\frac{96}{64} + \frac{80}{64} + \frac{72}{64} + \frac{68}{64} + \frac{66}{64} + \frac{65}{64} - 7

, which is

\frac{96 + 80 + 72 + 68 + 66 + 65}{64} - 7 = \frac{447}{64} - 7 = 6 \frac{63}{64} - 7 = - \frac{1}{64}

Final answer