Browse · MATH Print → jmc algebra intermediate Problem What is the value of x+y+z when 6x+5y−2z=−4 and 4x+5y+12z=54? Solution — click to reveal Add the two equations to find 10x+10y+10z=50. Dividing by 10 gives x+y+z=5. Final answer 5 ← Previous problem Next problem →