Browse · MATH
Printjmc
algebra senior
Problem
For some constants and let The function has the property that for all What is
Solution
Setting we get Since Hence, But for all so
Setting we get Since Hence, But for all so
Subtracting the equations and we get so From we get Hence,
Setting we get Since Hence, But for all so
Subtracting the equations and we get so From we get Hence,
Final answer
\frac{7}{3}