Find the remainder when 3y4−4y3+5y2−13y+4 is divided by 3y−2.
Solution — click to reveal
Using long division, \multicolumn2ry3\cline2−63y−2\multicolumn2r3y4\cline2−3\multicolumn2r0\multicolumn2r\cline3−4\multicolumn2r\multicolumn2r\cline4−5\multicolumn2r\multicolumn2r\cline5−6\multicolumn2r−32y23y4−2y3−2y3−2y30+911y−4y3+5y2+34y2+311y2+311y20−2795+5y2−13y−922y−995y−995y0−13y+4+27190−27824So the remainder is −2782.