Browse · MATH Print → jmc algebra junior Problem In right triangle ABC, we have AB=10, BC=24, and ∠ABC=90∘. If M is on AC such that BM is an angle bisector of △ABC, then what is cos∠ABM? Solution — click to reveal Since ∠ABC=90∘ and BM bisects ∠ABC, we have ∠ABM=45∘, so cos∠ABM=cos45∘=22. Final answer \frac{\sqrt{2}}{2} ← Previous problem Next problem →