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Ukraine geometry
Problem
On the sides , , of triangle such points , , are chosen that the lines , and meet at point . The perpendiculars are dropped from the point onto the sides of triangle. Lines , , are drawn through the feet of these perpendiculars, parallel to lines, symmetrical to , and with respect to angular bisectors of , and respectively. Prove that the lines , , meet at a point. 
Fig.28
Fig.28
Solution
The points , , , are cyclic, therefore $$
Techniques
Isogonal/isotomic conjugates, barycentric coordinatesCyclic quadrilateralsTriangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circleAngle chasing