smc

We simply ignore the floor of $x$. Then, we have $y$ = $2x+3$ = $3(x-2)+5$. Solving for $3x-1=2x+3$, we get $x=4$. For the floor of $x$, we have $x$ is between $4$ and $5$. Plugging in $8$ + $3$ = $11$ for $y$, we have $y=11$. We have $11+4.x$ = $\boxed{\text{ between 15 and 16}}$