Browse · harp Print → smc prealgebra senior Problem The sum of the two 5-digit numbers AMC10 and AMC12 is 123422. What is A+M+C? (A) 10 (B) 11 (C) 12 (D) 13 (E) 14 Solution — click to reveal AMC10+AMC12=123422 AMC00+AMC00=123400 AMC+AMC=1234 2⋅AMC=1234 AMC=21234=617 Since A, M, and C are digits, A=6, M=1, C=7. Therefore, A+M+C=6+1+7=14. Final answer E ← Previous problem Next problem →