Browse · MathNet
PrintBelarusian Mathematical Olympiad
Belarus counting and probability
Problem
girls and boys take part in a dancing party. It is known that Bob has a dance with every girl, and Ann has a dance with every boy. Moreover, for any two girls the number of the boys who have a dance with exactly one of these two girls is equal to .
Prove that
a) any girl, except for Ann, has a dance with exactly boys;
b) any boy, except for Bob, has a dance with exactly girls.
Prove that
a) any girl, except for Ann, has a dance with exactly boys;
b) any boy, except for Bob, has a dance with exactly girls.
Solution
We use the solution of Problem A.8.
a) Let Ann get number . Each vector , differs from at exactly positions and all entries of are equal to . Therefore, have exactly entries equal to , which proves the statement.
b) The same proof as in a). We consider the columns instead of the rows.
a) Let Ann get number . Each vector , differs from at exactly positions and all entries of are equal to . Therefore, have exactly entries equal to , which proves the statement.
b) The same proof as in a). We consider the columns instead of the rows.
Techniques
Counting two waysMatricesVectors