In right triangle ABC with A = 90^, we have AB =16 and BC = 24. Find A.

Since A = 90^, we have A = 90^= 1.

jmc

geometry intermediate

Problem

In right triangle

A B C

with

∠ A = 9 0^{\circ}

, we have

A B = 16

and

B C = 24

. Find

sin A

Solution

Since

∠ A = 9 0^{\circ}

, we have

sin A = sin 9 0^{\circ} = 1

Final answer