jmc

If there are $p$ words on each page, then we are given $136p\equiv 184(\mathrm{mod}203)$. We can divide both sides of the congruence by 8 since 8 is relatively prime to 203, and this yields $17p\equiv 23(\mathrm{mod}203)$. Checking integers which are 1 more than multiples of 203, we find that the modular inverse of 17 modulo 203 is 12. Therefore, $p\equiv 12(23)\equiv 73(\mathrm{mod}203)$. Therefore, each page has $\boxed{73}$ words on it.