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counting and probability intermediate

Problem

A magician designed an unfair coin so that the probability of getting a Head on a flip is . If he flips the coin three times, what is the probability that he flips more Heads than Tails? Express your answer as a common fraction.
Solution
The probability of flipping exactly two heads and one tail is . The probability of flipping exactly three heads and no tails is . So these are the two cases for having more heads than tails, and their sum is .
Final answer
\frac{81}{125}