Rotating the point (1,0) about the origin by 270^ counterclockwise gives us the point (0,-1), so 270^ = -1.

jmc

geometry junior

Problem

Compute

sin 27 0^{\circ}

Solution

Rotating the point

(1, 0)

about the origin by

27 0^{\circ}

counterclockwise gives us the point

(0, - 1)

, so

sin 27 0^{\circ} = - 1

Final answer

-1