jmc

We recognize $729x^3+8$ as a sum of cubes. We can write $729x^3+8$ as $(9x{)}^3+2^3$. We know the formula: $$a^3+b^3=(a+b)(a^2-ab+b^2).$$Thus, $$(9x{)}^3+2^3=(9x+2)(81x^2-18x+4).$$Therefore, $a+b+c+d+e=9+2+81-18+4=\boxed{78}$.