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prealgebra intermediate

Problem

If

8^{x} = 32

, then

x

equals:

(A)

4

(B)

\frac{5}{3}

(C)

\frac{3}{2}

(D)

\frac{3}{5}

Solution

Recognizing that

8 = 2^{3}

, we know that

2^{3 x} = 32

. Since

2^{5} = 32

, we have

2^{3 x} = 2^{5}

. Therefore,

x = \frac{5}{3}

. So our answer is

\frac{5}{3}

Final answer

B