Browse · MATH Print → jmc algebra intermediate Problem Given the equations 3x+y=17,5y+z=14 and 3x+5z=41, what is the value of the sum x+y+z? Solution — click to reveal Sum all three equations to find that 6x+6y+6z=17+14+41, from which x+y+z=72/6=12. Final answer 12 ← Previous problem Next problem →