jmc

The prime factorization of $210$ is $2\cdot 3\cdot 5\cdot 7$. It follows that the sum of the divisors of $210$ is equal to $(1+2)(1+3)(1+5)(1+7)$, as each factor of $210$ is represented when the product is expanded. It follows that the answer is equal to $3\cdot 4\cdot 6\cdot 8=\boxed{576}$.