Browse · MATH Print → jmc algebra senior Problem Let a and b be positive real numbers such that a+2b=1. Find the minimum value of a1+b2. Solution — click to reveal By AM-HM, 3a+b+b≥a1+b1+b13,so a1+b2≥a+2b9=9.Equality occurs when a=b=31, so the minimum value is 9. Final answer 9 ← Previous problem Next problem →