Browse · MATH Print → jmc algebra intermediate Problem The expression 12y2−65y+42 can be written as (Ay−14)(By−3), where A and B are integers. What is AB+A? Solution — click to reveal We see that 12y2−65y+42=(3y−14)(4y−3), thus A=3 and B=4. Hence, AB+A=15. Final answer 15 ← Previous problem Next problem →