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algebra senior

Problem

Cassandra sets her watch to the correct time at noon. At the actual time of 1:00 PM, she notices that her watch reads 12:57 and 36 seconds. Assuming that her watch loses time at a constant rate, what will be the actual time when her watch first reads 10:00 PM?
(A)
(B)
(C)
(D)
Solution
For every minutes that pass by in actual time, minutes pass by on Cassandra's watch. When her watch first reads, 10:00 pm, minutes have passed by on her watch. Setting up a proportion, where is the number of minutes that have passed by in actual time. Solve for to get minutes, or hours and minutes .
Final answer
C